0=(16t^2)-37t+20

Solution for 0=(16t^2)-37t+20 equation:

0=(16t^2)-37t+20

We move all terms to the left:

0-((16t^2)-37t+20)=0

We add all the numbers together, and all the variables

-(16t^2-37t+20)=0

We get rid of parentheses

-16t^2+37t-20=0

a = -16; b = 37; c = -20;
Δ = b2-4ac
Δ = 372-4·(-16)·(-20)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{89}}{2*-16}=\frac{-37-\sqrt{89}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{89}}{2*-16}=\frac{-37+\sqrt{89}}{-32}
$